appium之toast处理

Posted 2021-01-16 xiaohuhu

注意

toast要appium1.6.3以上版本才支持，appium1.4的版本就别浪费时间了

toast定位

1.先看下toast长什么样，如下图，像这种弹出来的消息"再按一次退出",这种就是toast了。

2.想定位toast元素，这里一定要注意automationName的参数必须是Uiautomator2才能定位到。

‘automationName‘: ‘Uiautomator2‘

# coding:utf-8
from appium import webdriver
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from time import sleep

desired_caps = {
                ‘platformName‘: ‘android‘,
                ‘deviceName‘: ‘127.0.0.1:62001‘,
                ‘platformVersion‘: ‘4.4.2‘,
                ‘appPackage‘: ‘com.baidu.yuedu‘,
                ‘appActivity‘: ‘com.baidu.yuedu.splash.SplashActivity‘,
                ‘noReset‘: ‘true‘,
                ‘automationName‘: ‘Uiautomator2‘
                }
driver = webdriver.Remote(‘http://127.0.0.1:4723/wd/hub‘, desired_caps)

# 等主页面activity出现
driver.wait_activity(".base.ui.MainActivity", 10)

driver.back()   # 点返回

# 定位toast元素
toast_loc = ("xpath", ".//*[contains(@text,‘再按一次退出‘)]")
t = WebDriverWait(driver, 10, 0.1).until(EC.presence_of_element_located(toast_loc))
print t

3.打印出来的结果，出现如下信息，说明定位到toast了

<appium.webdriver.webelement.WebElement (session="02813cce-9aaf-4754-a532-07ef7aebeb88", element="339f72c4-d2e0-4d98-8db0-69be741a3d1b")>

封装toast判断

1.单独写一个函数来封装判断是否存在toast消息，存在返回True,不存在返回False

def is_toast_exist(driver,text,timeout=30,poll_frequency=0.5):
    ‘‘‘is toast exist, return True or False
    :Agrs:
     - driver - 传driver
     - text   - 页面上看到的文本内容
     - timeout - 最大超时时间，默认30s
     - poll_frequency  - 间隔查询时间，默认0.5s查询一次
    :Usage:
     is_toast_exist(driver, "看到的内容")
    ‘‘‘
    try:
        toast_loc = ("xpath", ".//*[contains(@text,‘%s‘)]"%text)
        WebDriverWait(driver, timeout, poll_frequency).until(EC.presence_of_element_located(toast_loc))
        return True
    except:
        return False

参考代码

# coding:utf-8
from appium import webdriver
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
desired_caps = {
                ‘platformName‘: ‘Android‘,
                ‘deviceName‘: ‘127.0.0.1:62001‘,
                ‘platformVersion‘: ‘4.4.2‘,
                ‘appPackage‘: ‘com.baidu.yuedu‘,
                ‘appActivity‘: ‘com.baidu.yuedu.splash.SplashActivity‘,
                ‘noReset‘: ‘true‘,
                ‘automationName‘: ‘Uiautomator2‘
                }

def is_toast_exist(driver,text,timeout=30,poll_frequency=0.5):
    ‘‘‘is toast exist, return True or False
    :Agrs:
     - driver - 传driver
     - text   - 页面上看到的文本内容
     - timeout - 最大超时时间，默认30s
     - poll_frequency  - 间隔查询时间，默认0.5s查询一次
    :Usage:
     is_toast_exist(driver, "看到的内容")
    ‘‘‘
    try:
        toast_loc = ("xpath", ".//*[contains(@text,‘%s‘)]"%text)
        WebDriverWait(driver, timeout, poll_frequency).until(EC.presence_of_element_located(toast_loc))
        return True
    except:
        return False

if __name__ == "__main__":
    driver = webdriver.Remote(‘http://127.0.0.1:4723/wd/hub‘, desired_caps)

    # 等主页面activity出现
    driver.wait_activity(".base.ui.MainActivity", 10)

    driver.back()   # 点返回

    # 判断是否存在toast-‘再按一次退出‘
    print is_toast_exist(driver, "再按一次退出")