Go语言中利用append巧妙的删除slice切片中的元素

Posted 2020-11-19 livalon

package main

import (
    "fmt"
)

//删除函数
func remove(s []string, i int) []string {
    return append(s[:i], s[i+1:]...)
}

func main() {
    s := []string{"a", "b", "c"}
    fmt.Println(s)
    s = remove(s, 1)
    fmt.Println(s)
}