浏览器唤醒app

Posted 2020-10-22 0315cz

     </activity>
        <activity android:name="com.siyunetwork.wxpluginforunity.AwakenActivity">
            <intent-filter>
                <action android:name="android.intent.action.VIEW"/>
                <category android:name="android.intent.category.DEFAULT"/>
                <category android:name="android.intent.category.BROWSABLE"/>
                <data
                    android:host="com.siyunetwork.zhixiang.majiang"
                    android:scheme="app"/>
            </intent-filter>

        </activity>

安卓工程需要先写个activity用来唤醒

public class AwakenActivity extends Activity {

    String dataString;
    @Override
    protected void onCreate(Bundle savedInstanceState)
    {
        super.onCreate(savedInstanceState);
        Intent intent=getIntent();
        Intent intent1=new Intent();
        intent1.setClass(AwakenActivity.this, MainActivity.class); //设置跳转的Activity
        if (intent!=null)
        {
            String action=intent.getAction();
            dataString=intent.getDataString();
            Log.d("hhh",dataString);
            intent1.putExtra("dataString",dataString);
        }
        AwakenActivity.this.startActivity(intent1);

        finish();
    }

}

类里面重写onCreate方法，设置唤醒

    String dataString;


    @Override
    protected void onCreate(Bundle bundle) {
        super.onCreate(bundle);
        Intent intent=getIntent();
        dataString= intent.getStringExtra("dataString");
    }

    @Override
    protected void onNewIntent(Intent intent) {
        super.onNewIntent(intent);
        dataString= intent.getStringExtra("dataString");
        sendToUnity();
    }

再在mainActivity向unity发送数据

 

通过html唤醒

 

（以上内容仅供自己参考）