4 flappy bird

Posted 2020-10-21 LeoSirius

#include<stdio.h>
#include<stdlib.h>
#include<conio.h>
#include<windows.h>

int high, width;    //游戏画面大小
int bird_x, bird_y;    //小鸟的坐标
int bar1_y, bar1_xDown, bar1_xTop;    //障碍物
int score;         //得分，经过障碍物的个数

void gotoxy(int x, int y){    //类似于清屏函数
    HANDLE handle = GetStdHandle(STD_OUTPUT_HANDLE);
    COORD pos;
    pos.X = x;
    pos.Y = y;
    SetConsoleCursorPosition(handle, pos);
}

void startup(){
    high = 15;
    width = 20;
    bird_x = 3;
    bird_y = width / 3;
    bar1_y = width / 2;
    bar1_xDown = high / 3;
    bar1_xTop = high / 2;
    score = 0;
}

void show(){
    gotoxy(0, 0);     //清屏
    int i, j;
    for(i = 0; i < high; i++){
        for(j = 0; j < width; j++){
            if((i == bird_x) && (j == bird_y))
                printf("@");        //输出小鸟
            else if((j == bar1_y) && ((i < bar1_xDown) || (i > bar1_xTop)))
                printf("*");        //输出墙壁
            else
                printf(" ");
        }
        printf("\n");
    }
    printf("Score: %d\n", score);
}

void updateWithoutInput(){
    bird_x++;
    bar1_y--;
    if(bird_y == bar1_y){
        if((bird_x >= bar1_xDown) && (bird_x <= bar1_xTop))
            score++;
        else{
            printf("Failed\n");
            system("pause");
            exit(0);
        }
    }
    if(bar1_y <= 0){    //再生成一个障碍物
        bar1_y = width;
        int temp = rand() % (int)high*0.8;
        bar1_xDown = temp - high / 10;
        bar1_xTop = temp + high / 10;
    }
    Sleep(150);
}

void updateWithInput(){
    char input;
    if(kbhit()){
        input = getch();
        if(input == ‘ ‘){
            bird_x -= 2;
        }
    }
}

void main(){
    startup();
    while(1){
        show();
        updateWithoutInput();
        updateWithInput();
    }
}